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The point of intersection of the lines x-y+1=0 and x+y+5=0 is P. A circle with centre at (1, 0) passes through P. The tangent to the circle at P meets the x-axis at (k, 0).The value of k is : |
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Answer» Solution :`L_(1):X-y+1=0` `L_(2):x+y+5=0` `rArr""x= -3, y=-2` `rArr""P-=(-3, -2)` EQUATION of circle `(x-1)^(2)+y^(2)=20` `rArr""x^(2)+y^(2)-2x-19=0` Equation of tangent at P is `rArr""2x+y+8=0` `"PUT "y=0` `rArr""x=-4` `"Point is "(-4,0)` `rArr""k=-4` |
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