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The points `(1,1), (0, "sec"^(2) 0), ("cosec"^(2) 0,0 )` are collinear for-A. `0=(pi)/(2)`B. `0ne (npi)/(2)`C. `0=npi`D. None of these |
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Answer» Correct Answer - B `|{:(1,1,1),(0,sec^(2)theta,1),(cosec^(2)theta,0,1):}|` `rArr "sec"^(2) 0+ "cosec"^(2)0 -"sec" ^(2)0"cosec"^(2)0 =0` `rArr ("sin"^(2)0+"cos"^(2)0-1)/("cos"^(2)0"sin"^(2)0) =0` Which is ture if sin0 cos0`ne 0` `0 ne (npi)/(2)` |
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