InterviewSolution
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InterviewSolution
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The points `(-2,5), (3, -4) and (7, 10)` are the vertices of the triangle then triangle is: |
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Answer» Let `A(-2,5), B(3,-4) and C(7,10)` are the vertices of the given triangle. Then, `AB = sqrt((3-(-2))^2+(-4-5)^2) = sqrt106` `BC= sqrt((10 - (-4))^2+(7-3)^2) = sqrt212` `AC = sqrt((7-(-2))^2+(10-5)^2) = sqrt106` Now, `AB = AC` Also, `AB^2+AC^2 = BC^2` So, `ABC` is a right angled isoceles triangle. |
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