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Find the point on x-axis which is equidistant from points A(-1, 0) and B(5, 0). |
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Answer» Correct Answer - P(2, 0) Let the required point be P(x, 0). Then, `PA^(2) = PB^(2) rArr (x+1)^(2) + (0-0)^(2) = (x-5)^(2) + (0-0)^(2)` `rArr x^(2) +1 +2x = x^(2) + 25 -10x` `rArr 12x = 24 rArr x = 2` `therefore` the required point is P(2, 0). |
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