The points D, E, F divide −−→BC, −−→CA and −−→AB of the triangle ABC in the ratio 1:4, 3:2 and 3:7 respectively and the point K divides −−→AB in the ratio 1:3, then (−−→AD+−−→BE+−−→CF):−−→CK is equal to

The points D, E, F divide −−→BC, −−→CA and −−→AB of

1.	The points D, E, F divide −−→BC, −−→CA and −−→AB of the triangle ABC in the ratio 1:4, 3:2 and 3:7 respectively and the point K divides −−→AB in the ratio 1:3, then (−−→AD+−−→BE+−−→CF):−−→CK is equal to
Answer» The points $D, E, F$ divide $- - \to B C, - - \to C A$ and $- - \to A B$ of the triangle $A B C$ in the ratio $1 : 4, 3 : 2$ and $3 : 7$ respectively and the point $K$ divides $- - \to A B$ in the ratio $1 : 3$ , then $(- - \to A D + - - \to B E + - - \to C F) : - - \to C K$ is equal to