Saved Bookmarks
| 1. |
The population of a town increase by 10% annually. If the present population is 22000, find it population a year ago. |
|
Answer» Present population of town = 22000 Rate of increase in population annually = 10% Let the population 1 year ago be x . Now, (x + 10% of x) = 22000 (x + x/10) = 22000 11x/10 = 22000 x = 22000 x 10/11 x = 20000 So, The population 1 year ago will be 20000. |
|