InterviewSolution
Saved Bookmarks
| 1. |
The population of a town increases by 10% annually. If the present population is 600000, what will be its population after 2 years? |
|
Answer» Present population of town = 60000 Percentage increase in population annually = 10% Hence , Population of town after 2 years = present population \(\times[{\frac{100+\text{% increase}}{100}}]\)time (time in years) \(={60000}\times\frac{100+10}{100}\times\frac{100+10}{100}\) \(={60000}\times\frac{110}{100}\times\frac{110}{100}\) = 72600 |
|