The positiion vectors of two point masses 10 kg and 5 kg are (3hati+2hatj+4hatk)m and (3hati+6hatj+5hatk)m respectively. Locate the position of center of mass.

The positiion vectors of two point masses 10 kg and 5 kg are (3hati+2h

1.	The positiion vectors of two point masses 10 kg and 5 kg are (3hati+2hatj+4hatk)m and (3hati+6hatj+5hatk)m respectively. Locate the position of center of mass.
Answer» Solution :`m_(1)=10 kg` `m_(2)= 5kg` `vecr_(1)=(-3hati+2hatj+4hatk)m` `vecr_(2)=(3hati+6hatj+5hatk)m` `vecr=(m_(1) vecr_(1)+m_(2) vecr_(2))/(m_(1)+m_(2))` `:. vecr=(10(-3hati+2hatj+4hatk)+5(3hati+6hatj+4hatk))/(10+5)` `=(-30 HATI+20 hatj+40 hatk+15hati+30 hatj+25 hatk)/(15)=(-15 hatk+50 hatj+65 hatk)/(15)` `vecr=(-hati+(10)/(3) hatj+(13)/(3)hatk)` The center of mass is located at position `vecr`