The position of a particle is given by vecr = hati + 2hatj - hatk and its linear momentum is given by vecp= 3hati+4 hatj - 2hatk. Then its angular momentum, about the origin is perpendicular to

The position of a particle is given by vecr = hati + 2hatj - hatk and

1.	The position of a particle is given by vecr = hati + 2hatj - hatk and its linear momentum is given by vecp= 3hati+4 hatj - 2hatk. Then its angular momentum, about the origin is perpendicular to
Answer» yz-plane Z-axis y-axis x-axis Solution :`vecL = vecr xx vecp = \|{:(hati , HATJ , hatk), (1, 2, -1) , (3 , 4 , -2):}\|` `= hati (-4 + 4 ) - hatj (-2 + 3) + hatk (4 - 6) = 0 hati 0 1 hatj - 2hatk` `vecL` has components along-yaxis and -z axis but it has no component in the x-axis . The angular MOMENTUM is in yz plane i.e., perpendicular to x-axis .