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The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to theA. x-axisB. y-axisC. z-axisD. yz-plane |
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Answer» Correct Answer - a Here, `vecr=hati+2hatj-hatk, vecp=3hati+4hatj-2hatk` `vecL= vecr xx vecp= |{:[hati, hatj, hatk],[1,2,-1],[3,4,-2]:}|=hati(-4+4)+hatj(-3+2)+hatk(4-6)=0hati-1hatj-2hatk` `vecL` has component along `-y` axis and `-z` axis but it has no component along the x-axis. The angular momentum `vecL` is in yz-plane. i.e., perpendicular to x-axis. |
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