The position of an object moving along x-axis is given by x =a + bt ^(2) where a8.5 m, b=2.5 ms ^(-2) and t is and t = 2.0 s. What is the average velocity between t = 2.0 s and t = 4.0s?

The position of an object moving along x-axis is given by x =a + bt ^(

1.	The position of an object moving along x-axis is given by x =a + bt ^(2) where a8.5 m, b=2.5 ms ^(-2) and t is and t = 2.0 s. What is the average velocity between t = 2.0 s and t = 4.0s?
Answer» Solution :In notation of differential calculus, the VELOCITY is `upsilon = (dx)/(dt)=(d)/(dt)(a+bt^(2))=2b t=5.0 t MS^(-1)` At t = 0 s, `"" upsilon = 0 ms^(-1)`and at t = 2.0 s, `upsilon =10 ms^(-1)`. Average velocity `=(x(4.0)-x(2.0))/(4.0-2.0)` `=(a+16b-a-4b)/(2.0)=6.0xx B` `=6.0xx2.5=15 ms^(-1)`.