The position of moving object at time 't', x=2t^(3), then find the acc

1.	The position of moving object at time 't', x=2t^(3), then find the acceleration.
Answer» Solution :`X = 2t ^(3)` `v = (dx)/(dt) = (d)/(dt) (2t ^(3))` `v = 6t ^(2)` Now, acceleration `a = (DV)/(dt) = (d)/(dt) ( 6t ^(2))` `therefore a = 12 t`

Discussion