The position vector of a particle is vecr=4t^(2)hati+2thatj+3thatk. The acceleration of a particle is having only

The position vector of a particle is vecr=4t^(2)hati+2thatj+3thatk. Th

1.	The position vector of a particle is vecr=4t^(2)hati+2thatj+3thatk. The acceleration of a particle is having only
Answer» X-component Y-component Z-component X-Y component Solution :`vecr=4t^(2)hati+2thatj+3hatk,VECV=(dvecr)/(DT)=8thati+2hatj` `a=(d^(2)R)/(dt^(2))=8hatia` is having only X-component.