InterviewSolution
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InterviewSolution
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The position vector of a particle `vec(R )` as a funtion of time is given by: `vec(R )= 4sin(2pit)hat(i)+4cos(2pit)hat(j)` Where `R` is in meters, `t` is in seconds and `hat(i)` and `hat(j)` denote until vectors along x-and y- directions, respectively Which one of the following statements is wrong for the motion of particle ?A. Path of the particle is a circle of radius 4 meterB. Acceleration vector is along `-vecR`C. Magnitude of acceleration vector is `(v^(2))/(R)` where v is the velocity of particleD. Magnitude of the velocity of particle is 8 meter/second |
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Answer» Correct Answer - D `vecR=4sin(2pit)hati+4cos(2pit)hatj` `x=4sin2pit` . . . (1) `y=4cos2pit` . . . (2) (1) `x^(2)+y^(2)=4(sin^(2)2pit+cos^(2)2pit)` `x^(2)+y^(2)=4^(2)` equation of circle and radius 4m (2) `veca=(V^(2))/(R)(-hatR)` (3) `a=(V^(2))/(R)` (4) `V_(x)=+4(cos2pit)(2pi)` and `V_(y)=-4(sin2pit)(2pi)` `V=sqrt(V_(x)^(2)+V_(x)^(2))` `=sqrt((8pi)^(2)(cos^(2)2pit+sin^(2)2pit))` `V=8pi` so `4^(th)` option is incorrect. |
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