The position vector of a point P is →r=x^i+y^j+z^k, when x,y,zϵ N a – InterviewSolution

1.	The position vector of a point P is →r=x^i+y^j+z^k, when x,y,zϵ N and →a=^i+^j+^k.If→r.→a=10, the number of possible position of P is
Answer» The position vector of a point P is $\to r = x^i + y^j + z^k$ , when $x, y, z ϵ$ N and $\to a =^i +^j +^k . I f \to r . \to a = 10$ , the number of possible position of P is

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