The position vector of four identical masses of mass 1 kg each are →r1=(^i+2^j+7^k),→r2=(3^i+5^j+^k), →r3=(6^i+2^j+3^k) and →r4=(2^i−^j+5^k). Find the position vector of their centre of mass.

The position vector of four identical masses of mass 1 kg each are →

1.	The position vector of four identical masses of mass 1 kg each are →r1=(^i+2^j+7^k),→r2=(3^i+5^j+^k), →r3=(6^i+2^j+3^k) and →r4=(2^i−^j+5^k). Find the position vector of their centre of mass.
Answer» The position vector of four identical masses of mass $1 kg$ each are $_{1} = (^i + 2^j + 7^k),_{2} = (3^i + 5^j +^k),$ $_{3} = (6^i + 2^j + 3^k)$ and $_{4} = (2^i -^j + 5^k)$ . Find the position vector of their centre of mass.

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The position vector of four identical masses of mass 1 kg each are →r1=(^i+2^j+7^k),→r2=(3^i+5^j+^k), →r3=(6^i+2^j+3^k) and →r4=(2^i−^j+5^k). Find the position vector of their centre of mass.

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