The position vector of four particles of masses m1=2 kg, m2=4 kg, m3=6 kg, m4=8 kg are →r1=2^i+3^j+0^k, →r2=0^i+2^j+3^k, →r3=2^i+0^j+3^k; →r4=2^i+3^j+3^k. The position vector of their centre of mass is given by

The position vector of four particles of masses m1=2 kg, m2=4 kg, m3=6

1.	The position vector of four particles of masses m1=2 kg, m2=4 kg, m3=6 kg, m4=8 kg are →r1=2^i+3^j+0^k, →r2=0^i+2^j+3^k, →r3=2^i+0^j+3^k; →r4=2^i+3^j+3^k. The position vector of their centre of mass is given by
Answer» The position vector of four particles of masses $m_{1} = 2 kg, m_{2} = 4 kg, m_{3} = 6 kg, m_{4} = 8 kg$ are $_{1} = 2^i + 3^j + 0^k,_{2} = 0^i + 2^j + 3^k,_{3} = 2^i + 0^j + 3^k;_{4} = 2^i + 3^j + 3^k$ . The position vector of their centre of mass is given by

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The position vector of four particles of masses m1=2 kg, m2=4 kg, m3=6 kg, m4=8 kg are →r1=2^i+3^j+0^k, →r2=0^i+2^j+3^k, →r3=2^i+0^j+3^k; →r4=2^i+3^j+3^k. The position vector of their centre of mass is given by

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