The position vector of three particles of masses m1=1 kg, m2=2 kg and m3=3 kg are →r1=(^i+4^j+^k) m, →r2=(^i+^j+^k) m and →r3=(2^i−^j−2^k) m respectively. The position vector of their centre of mass is

The position vector of three particles of masses m1=1 kg, m2=2 kg and

1.	The position vector of three particles of masses m1=1 kg, m2=2 kg and m3=3 kg are →r1=(^i+4^j+^k) m, →r2=(^i+^j+^k) m and →r3=(2^i−^j−2^k) m respectively. The position vector of their centre of mass is
Answer» The position vector of three particles of masses $m_{1} = 1 kg, m_{2} = 2 kg$ and $m_{3} = 3 kg$ are ${\to r}_{1} = (^i + 4^j +^k) m, {\to r}_{2} = (^i +^j +^k) m$ and ${\to r}_{3} = (2^i -^j - 2^k) m$ respectively. The position vector of their centre of mass is

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The position vector of three particles of masses m1=1 kg, m2=2 kg and m3=3 kg are →r1=(^i+4^j+^k) m, →r2=(^i+^j+^k) m and →r3=(2^i−^j−2^k) m respectively. The position vector of their centre of mass is

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