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The position vectors of the points A, B, C and D are 4hati+3hatj-hatk, 5hati+2hatj+2hatk, 2hati-2hatj-3hatk and 4hati-4hatj+3hatk respectively. Show that AB and CD are parallel. |
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Answer» Solution :Given that the POSITION vector of A = `4hati+3hatj-hatk` position vector of B = `5hati+2hatj+2hatk` position vector of C = `2hati-2hatj-3hatk` position vector of D = `4hati-4hatj+3hatk` Then `VEC(AB) = (5hati+2hatj+2hatk)-(4hati+3hatj-hatk)` =`hati-hatj+3hatk` `vec(CD) = (4hati-4hatj+3hatk)-(2hati-2hatj-3hatk)` =`2hati-2hatj+6hatk` =`2(hati-hatj+3hatk) = 2vec(AB)`. |
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