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The position vectors of vertices of a Delta ABC are 4hat(i)-2hat(j), hat(i)-3hat(k) and -hat(i)+5hat(j)+hat(k) respectively, then angle ABC is equal to |
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Answer» `pi/6` `BC = -2 hati+hatj+4hatk` and `AB*BC=6+6-12=0` `RARR""/_ABC=pi/2` |
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