InterviewSolution
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InterviewSolution
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The position x of a partical at time t is given by `x =(V_0)/(a) (1 -e^(9-at))` where `V_0` is a constant and a gt 0. The dimensions of `V_0` and a are.A. `M^0 L T^(-1) and T^(-1)`B. `M^0 L T^0 and T^(-1)`C. `M^0 L T^(-1) and L T^(-2)`D. `M^0 L T^(-1) and T` |
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Answer» Correct Answer - (a) As axxt is dimensionless. `:. a = (1)/(t) = (1)/(T) = [T^(-1)]` Also,` x = (V_0)/(a), V_0 = x a = [LT^(-1)]` |
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