The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)), where V_(0) is constant and a gt 0. The dimensions of V_(0) and a are

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(

1.	The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)), where V_(0) is constant and a gt 0. The dimensions of V_(0) and a are
Answer» `[M^(0)LT^(-1)]` and `[M^(0)L^(0)T^(-1)]` `[M^(0)LT^(0)]` and `[M^(0)LT^(-1)]` `[M^(0)LT^(-1)]` and `[MLT^(-2)]` `[M^(0)LT^(-1)]` and `[M^(0)LT]` Solution :As`a xx t` is dimensionless, `:. [a] = (1)/([t])= (1)/([T])= [T^(-1)]= [M^(0)L^(0)T^(-1)]` ALSO `[x]= ([V_(0)])/([a])` or `[V_(0)]= [x][a]= [L][M^(0)L^(0)T^(-1)] = [M^(0)LT^(-1)]`