InterviewSolution
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InterviewSolution
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The position (x) of a particle of mass 1 kg moving along X-axis at time t is given by `(x=1/2 t^(2))` metre. Find the work done by force acting on it in time interval from `t=0` to `t=3 s`.A. 4.2 JB. 5.4 JC. 4.6 JD. 4.5 J |
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Answer» Correct Answer - D `x=1/2 t^(2)` `implies v=(dx)/(dt)=1/2 (2t)=t` `:.` At `t=0, v_(i)=0 implies` At `t=3 s, v_(f)=3 ms^(-1)` According to work -energy theorem, `W=Delta K=K_(f)-K_(i)` `=1/2 mv_(f)^(2)-1/2 mv_(i)^(2)=1/2xx1xx3^(2)=4.5 J` |
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