1.

The positive root of x^(2)-78.8=0 after first approximation by Newton Raphson method assuming initial approximation to the root is 14, is

Answer»

9.821
9.814
9.715
9.915

Solution :Here, `x_(0)=14, f(x)=x^(2)-78.8`
`and f'(x)=2x`
`THEREFORE x_(1)=x_(0)-(f(x_(0)))/(f'(x_(0)))`
`=14-((14)^(2)-(78.8))/(2xx14)=9.814`


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