1.

The possible mechanism for the reaction : 2" H"_(2)+2" NO"to"N"_(2)+2" H"_(2)"O" is (i) 2 "NO"iff"N"_(2)"O"_(2)" (ii) ""N"_(2)"O"+"H"_(2)"O"("slow")" (iii) ""N"_(2)"O"+"H"_(2)to"N"_(2)+"H"_(2)"O"("fast") What is (i) the rate law for the reaction (ii) the order of the reaction ?

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Solution :From (II), Rate `=k[N_(2)O_(2)][H_(2)]`
From (i), `K_(EQ)=([N_(2)O_(2)])/([NO]^(2))" or "[N_(2)O_(2)]=K_(eq)[NO]^(2):." Rate "=k." K"_(eq)[NO]^(2)[H_(2)]=k'[NO]^(2)[H_(2)]`


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