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The possible number of stereoisomers of the product of following reaction would be : `Ph-CH=CH-undersetunderset(CH_3)(|)CH-CHOoverset(NH_2OH)to`A. 2B. 4C. 6D. 8 |
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Answer» Correct Answer - D Product=`Ph-CH=CH-undersetunderset(CH_3)(|)CH-CH=NOH` Total number of stereoisomers =`2^(n)=2^(3)=8` (n = number of stereo centres (G.I.+O.I.)=2+1=3) |
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