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The potential drop across the `3 Omega` resistor is A. `1 V`B. `1.5 V`C. `2 V`D. `3 V` |
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Answer» Correct Answer - A (a) Equivalent resistance `R = 4 + (3 xx 6 )/(3 + 6) = 6 Omega` and main current `i= (E)/(R ) = (3)/(6) = 0.5 A` Now potential difference across the combination of `3 Omega` and `6 Omega, V = 0.5 xx ((3 xx 6)/(3 + 6)) = 1`volt The same potential difference, also develops across `3 Omega` resistance. |
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