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The potential energy as a function of displacement for an oscillator `u=8x^(2)` joule. The magnitude of the force on the oscillator of mass 0.5 kg placed at x = 0.2 m isA. 1.6 NB. 3.2 NC. 0.8 ND. 4.8 N |
Answer» Correct Answer - B `u=8x^(2)` `PE=8x^(2)` `(1)/(2)kx^(2)=8x^(2) therefore k=16` `F=(1)/(2)kx=(1)/(2)xx16xx0.2=1.6N` |
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