InterviewSolution
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InterviewSolution
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The potential energy function for a particle executing linear SHM is given by `V(x)= 1/2kx^2` where k is the force constant of the oscillator. For `k = 0.5 Nm^(-1)`, the graph of V(x) versus x is shown in the figure A particle of total energy E turns back when it reaches `x=pmx_m`.if V and K indicate the potential energy and kinetic energy respectively of the particle at `x= +x_m`,then which of the following is correct? A. V=0, K=EB. V=E, K=0C. V lt K, K=0D. V=0, K lt E |
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Answer» Correct Answer - B At any instant, the total energy of an oscillator is the sum of kinetic energy and potential energy. Total energy, E=K + V At `x= +x_m`, the particle turns back, therefore its velocity at this point is zero, i.e. v=0 `therefore` K=0 `therefore E=1/2kx^2 =V` |
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