The potential energy of a body of mass 2 kg in a conservative field is U=(6x−8y) J. If the initial velocity of the body is →u=(−1.5^i+2^j) m/s, then the total distance travelled by the particle in the first two seconds is

The potential energy of a body of mass 2 kg in a conservative field is

1.	The potential energy of a body of mass 2 kg in a conservative field is U=(6x−8y) J. If the initial velocity of the body is →u=(−1.5^i+2^j) m/s, then the total distance travelled by the particle in the first two seconds is
Answer» The potential energy of a body of mass $2 kg$ in a conservative field is $U = (6 x - 8 y) J$ . If the initial velocity of the body is $\to u = (- 1.5^i + 2^j) m/s$ , then the total distance travelled by the particle in the first two seconds is

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The potential energy of a body of mass 2 kg in a conservative field is U=(6x−8y) J. If the initial velocity of the body is →u=(−1.5^i+2^j) m/s, then the total distance travelled by the particle in the first two seconds is

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