1.

The potential energy of a certain spring when stretched through a distance S is 10 joule. The amount of work in joule) that must be done on this spring to stretch it through additional distance S will be

Answer»

30 
40 
10 
20 

Solution :`U = 1/2 kS^2 = 10 J "" …(i)`
`U. = 1/2 k (S + S)^2 = U (1/2 kS^2) = 40 J "" ` (using (i))
`:. W = U. - U = 40 J - 10 J = 30 J`.


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