The potential energy of a conservative system is given by V(x) = (x^2

1.	The potential energy of a conservative system is given by V(x) = (x^2 – 3x) joule. Then its equilibrium position is at
Answer» `X= 1.5 m` ` x = 2 m` `x= 2.5 m` ` x = 3 m` Solution :`V(x) = (x^2 - 3X)J` For a conservative field, FORCE, `F = - (dV)/(dx)` `:. F = - (d)/(dx) (x^2- 3x) = - (2x - 3) = -2x + 3` At equilibrium position, `F = 0` `:. -2x + 3 = 0 or x = 3/2 m = 1.5 m`.

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