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The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J and its amplitude is 0.01m, find its time period |
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Answer» Solution :`(1)/(2)kA^(2)= (9-5)= 4J` `:. K= (8)/(A^(2))= (8)/(0.01)^(2)= 8 xx 10^(4)N//m` `T= 2pisqrt((m)/(k))= 2pisqrt((2)/(8 xx 10^(4)))= (PI)/(100) s` |
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