1.

The potential energy of a long spring when stretched by 2cm is U. If the spring is stretched by 8 cm the potential energy stored in it is……….

Answer»

`8U`
`16U`
`(U)/(4)`
`4U`

Solution :Potential energy STORED in spring `U= (1)/(2) kx^(2)`
For `x=2, U= (1)/(2)k(2)^(2)= 4xx (k)/(2)= 2K"""……"(1)`
For `x=8 cm," NEW "U= U.= (1)/(2) k(8)^(2)= (1)/(2)k(64)`
`= 32k= 16(2k)`
`THEREFORE U.= 16U""therefore " from equation (1) ")`


Discussion

No Comment Found