InterviewSolution
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InterviewSolution
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The potential energy of a partical of mass `2 kg` moving in `y-z` plane is given by `U=(-3y+4z)J` where `y` and `z` are in metre. The magnitude of force ( in newton ) on the particle is `:` |
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Answer» Here, `U=(-3 y + 4 z)J` As `vec(F)=-(deltau)/( deltay)hat(j)- (deltau)/( deltaz) hat(k)` `:. vec(F) 3 hat (j) - 4 hat(k)` `|vec(F)|=sqrt(3^(2)+(-4)^(2))=sqrt(9+16)=5N` |
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