Saved Bookmarks
| 1. |
The potential energy of a particle executing `SHM` change from maximum to minimum in `5 s`. Then the time period of `SHM` is:A. `5s`B. `10s`C. `15s`D. `20s` |
|
Answer» Correct Answer - D `P.E` is maximum at exteement position and minimum at mean position. Time to go from extreme position to mean position is `,t=(T)/(4),` where `T` is time period of `SHM 5s=(T)/(4)` `rArr T=20s`. |
|