1.

The potential energy of a particle in a force field is U=Ar2−Br where A and B are positive constants and r is the distance of particle from the centre of the field For stable equilibrium the distance of the particle is 1)A/B 2)B/A 3)B/2A 4)2A/B

Answer»

The potential energy of a particle in a force field is U=Ar2Br where A and B are positive constants and r is the distance of particle from the centre of the field For stable equilibrium the distance of the particle is

1)A/B

2)B/A

3)B/2A

4)2A/B



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