The potential energy of a particle of mass 0.1kg, moving along the x-axis, is given by U(x) = U_(0)(1 - cos x) where U_(0) is in meter. It can be concluded that

The potential energy of a particle of mass 0.1kg, moving along the x-a

1.	The potential energy of a particle of mass 0.1kg, moving along the x-axis, is given by U(x) = U_(0)(1 - cos x) where U_(0) is in meter. It can be concluded that
Answer» The particle is ACTED upon by a CONSTANT FORCE The speed of the particle is maximum at x = 2m The particle executes SHM The PERIOD of oscillation of the particle is Answer :B::C::D