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The potential energy of a particle of mass `m` free to move along the x-axis is given by `U=(1//2)kx^2` for `xlt0` and `U=0` for `xge0` (x denotes the x-coordinate of the particle and k is a positive constant). If the total mechanical energy of the particle is E, then its speed at `x=-sqrt(2E//k)` isA. zeroB. `sqrt((2E)/(m))`C. `sqrt((E)/(m))`D. `sqrt((E )/(2m))` |
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Answer» Correct Answer - A From conservation of energy `K.E + P.E = E` or `K.E = E - (1)/(2) kx_(2)` K.E at `x =- sqrt((2E)/(k))` is `E -(1)/(2)k((2E)/(k))=0` `:.` The speed of particle at `x = - sqrt((2E)/(k))` is zero. |
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