The potential energy of a particle that is free to move along x−axis is given by U=(x3−x22)J, where x is in meter. The particle is initially at x=0. Find the magnitude of force at x=2 m.

The potential energy of a particle that is free to move along x−axis

1.	The potential energy of a particle that is free to move along x−axis is given by U=(x3−x22)J, where x is in meter. The particle is initially at x=0. Find the magnitude of force at x=2 m.
Answer» The potential energy of a particle that is free to move along $x - axis$ is given by $U = (x^{3} - \frac{x^{2}}{2}) J$ , where $x$ is in $meter$ . The particle is initially at $x = 0$ . Find the magnitude of force at $x = 2 m$ .

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The potential energy of a particle that is free to move along x−axis is given by U=(x3−x22)J, where x is in meter. The particle is initially at x=0. Find the magnitude of force at x=2 m.

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