The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.A. `[ML^(7//2)T^(-2)]`B. `[ML^(11//2)T^(-2)]`C. `[M^(2)L^(9//2)T^(-2)]`D. `[ML^(13//2)T^(-3)]`

The potential energy of a particle varies with distance `x` from a fix

1.	The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.A. `[ML^(7//2)T^(-2)]`B. `[ML^(11//2)T^(-2)]`C. `[M^(2)L^(9//2)T^(-2)]`D. `[ML^(13//2)T^(-3)]`
Answer» Correct Answer - B

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The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.A. `[ML^(7//2)T^(-2)]`B. `[ML^(11//2)T^(-2)]`C. `[M^(2)L^(9//2)T^(-2)]`D. `[ML^(13//2)T^(-3)]`

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