1.

The potential energy of a projectile at its maximum height is equal to its kinetic energy there. If the velocity of projection is `20 m//s^(-1)`,its time of flight is `(g=10 m//s^(2))`A. `2s`B. `2sqrt2s`C. `1/2s`D. `1/sqrt2s`

Answer» Correct Answer - B
`P.E=K.ErArr1/2"mu"^(2) sin^(2)theta=1/2"mu"^(2) sin^(2)theta`
use`T=(2u sin theta)/g`


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