1.

The potential energy of a simple harmonic oscillator when the particle is halt way to its end point is (E is total energy) .......... .

Answer»

`(2)/(3)E`
`(1)/(3)E`
`(1)/(4)E`
`(1)/(2)E`

Solution :`PE=(1)/(2)Kx^(2) IMPLIES PE_(v_(2))=(1)/(2)K((A)/(2))^(2)=(1)/(4)((1)/(2)KA^(2))`
`PE_(v_(2))=(1)/(4)E`


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