1.

The potential energy of a simple harmonic oscillator when the particle is half way to its end point is……….(where E is total (mechanical) energy)

Answer»

`(1)/(2)E`
`(2)/(3)E`
`(1)/(8)E`
`(1)/(4)E`

Solution :`E= (1)/(2) m omega^(2) A^(2)`
POTENTIAL energy `= (1)/(2)m omega^(2) y^(2)`
`=(1)/(2)m omega^(2) (A/2)^(2) = (E )/(4)`.


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