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The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9 J and its amplitude is 0.01m, its time period would be |
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Answer» Here, ½ kA2 = (9 – 5) J = 4 J So, k = 8/A2 = 8/(0.01)2 = 8 x104 N/m T = 2π√m/k = 2π√[2/(8 x 104)] = (π/100) s |
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