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The potential energyof a system under theinfluenceof conservativeforce at positionx isV(x) =[3x^(2)+4x+5].At x = 2 m the conservativeforce actingon the system is ………. |
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Answer» `-20` N ` :. F = (dU)/(DX) = d/(dx) [3x^(2) +4x+5] ` ` :. F = 6x + 4` If x = 2, them `F = 6 xx2+4 = 16 N ` F = 16 N ` :. F = 16 N ` |
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