The potential of an electrode is represented as Pt. (0.25 atm)//H^(+)

1.	The potential of an electrode is represented as Pt. (0.25 atm)//H^(+) [0.5]
Answer» 0 0.018 V 0.059 V 0.118 V Solution :`E_(H2)=E_(H2)^(@)+(0.059)/(2)"LOG"([H^(+)]^(2))/([H_(2)])` `=0+(0.059)/(2)"log"((0.5)^(2))/((0.25)^(2))=`Zero

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