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The potential of C is : A. 51 VB. 0C. `+3V`D. 69V |
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Answer» Correct Answer - D By KVL in each branch `v_(o)=(V_(1)/(R_(1))+(V_(2))/(R_(2))+(V_(3))/(R_(3)))/((1)/(R_(1))+1/(R_(2))+1/R_(3))` `9=(3/1+(Vc)/(2)+0)/(1+1/2+1/(0.5))` `(Vc)/(2)-3=9((1)/(2)+2)` `(Vc)/(2)-3=9[(7)/(2)]` `(Vc)/(2)=(63)/(2)+3` Vc = 69 V |
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