The potential of the cell at 25∘C isPt|H2(1 atm)|CH3COONa(0.1M)+CH3C – InterviewSolution

InterviewSolution

1.	The potential of the cell at 25∘C isPt\|H2(1 atm)\|CH3COONa(0.1M)+CH3COOH(0.01M)\|\|NH4Cl(0.2M)+NH4OH(0.1M)\|H2(1 atm)\|PtGiven: pKa of CH3COOH and pKb of NH4OH=4.74
Answer» The potential of the cell at $25^{\circ} C$ is $P t \| H_{2} (1 atm) \| C H_{3} C O O N a (0.1 M) + C H_{3} C O O H (0.01 M) \| \| N H_{4} C l (0.2 M) + N H_{4} O H (0.1 M) \| H_{2} (1 atm) \| P t$ Given: $p K_{a}$ of $C H_{3} C O O H$ and $p K_{b}$ of $N H_{4} O H = 4.74$

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