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| 1. |
The potentiometer wire of resistance R is connected in series with a cell of e.m.f. E and of resistance `R_(h)`. The current flowing through the potentiometer wire isA. `I=(E)/(R+r+R_(h))`B. `I=(E)/(R+r)`C. `I=(RE)/(R_(h)+r)`D. `I=(E)/(R)` |
| Answer» Correct Answer - A | |